# Asymptotic Analysis

Why performance analysis?
There are many important things that should be taken care of, like user friendliness, modularity, security, maintainability, etc. Why to worry about performance?
The answer to this is simple, we can have all the above things only if we have performance. So performance is like currency through which we can buy all the above things. Another reason for studying performance is – speed is fun!

Given two algorithms for a task, how do we find out which one is better?

One naive way of doing this is – implement both the algorithms and run the two programs on your computer for different inputs and see which one takes less time. There are many problems with this approach for analysis of algorithms.
1) It might be possible that for some inputs, first algorithm performs better than the second. And for some inputs second performs better.
2) It might also be possible that for some inputs, first algorithm perform better on one machine and the second works better on other machine for some other inputs.

Asymptotic Analysis is the big idea that handles above issues in analyzing algorithms. In Asymptotic Analysis, we evaluate the performance of an algorithm in terms of input size (we don’t measure the actual running time). We calculate, how does the time (or space) taken by an algorithm increases with the input size.
For example, let us consider the search problem (searching a given item) in a sorted array. One way to search is Linear Search (order of growth is linear) and other way is Binary Search (order of growth is logarithmic). To understand how Asymptotic Analysis solves the above mentioned problems in analyzing algorithms, let us say we run the Linear Search on a fast computer and Binary Search on a slow computer. For small values of input array size n, the fast computer may take less time. But, after certain value of input array size, the Binary Search will definitely start taking less time compared to the Linear Search even though the Binary Search is being run on a slow machine. The reason is the order of growth of Binary Search with respect to input size logarithmic while the order of growth of Linear Search is linear. So the machine dependent constants can always be ignored after certain values of input size.
Does Asymptotic Analysis always work?
Asymptotic Analysis is not perfect, but that’s the best way available for analyzing algorithms. For example, say there are two sorting algorithms that take 1000nLogn and 2nLogn time respectively on a machine. Both of these algorithms are asymptotically same (order of growth is nLogn). So, With Asymptotic Analysis, we can’t judge which one is better as we ignore constants in Asymptotic Analysis.
Also, in Asymptotic analysis, we always talk about input sizes larger than a constant value. It might be possible that those large inputs are never given to your software and an algorithm which is asymptotically slower, always performs better for your particular situation. So, you may end up choosing an algorithm that is Asymptotically slower but faster for your software.

# Worst, Average and Best Cases

Take an example of Linear Search and analyze it using Asymptotic analysis.
We can have three cases to analyze an algorithm:
1) Worst Case
2) Average Case
3) Best Case
Let us consider the following implementation of Linear Search.
`#include <stdio.h>`
`// Linearly search x in arr[].  If x is present then return the index,`
`// otherwise return -1`
`int` `search(``int` `arr[], ``int` `n, ``int` `x)`
`{`
`    ``int` `i;`
`    ``for` `(i=0; i<n; i++)`
`    ``{`
`       ``if` `(arr[i] == x)`
`         ``return` `i;`
`    ``}`
`    ``return` `-1;`
`}`
`/* Driver program to test above functions*/`
`int` `main()`
`{`
`    ``int` `arr[] = {1, 10, 30, 15};`
`    ``int` `x = 30;`
`    ``int` `n = ``sizeof``(arr)/``sizeof``(arr);`
`    ``printf``(``"%d is present at index %d"``, x, search(arr, n, x));`
`    ``getchar``();`
`    ``return` `0;`
`}`

`Worst Case Analysis (Usually Done)`
`In the worst case analysis, we calculate upper bound on running time of an algorithm. We must know the case that causes maximum number of operations to be executed. For Linear Search, the worst case happens when the element to be searched (x in the above code) is not present in the array. When x is not present, the search() functions compares it with all the elements of arr[] one by one. Therefore, the worst case time complexity of linear search would be Θ(n).`
``` Average Case Analysis (Sometimes done)  In average case analysis, we take all possible inputs and calculate computing time for all of the inputs. Sum all the calculated values and divide the sum by total number of inputs. We must know (or predict) distribution of cases. For the linear search problem, let us assume that all cases are uniformly distributed (including the case of x not being present in array). So we sum all the cases and divide the sum by (n+1). Following is the value of average case time complexity. Best Case Analysis (Bogus)  In the best case analysis, we calculate lower bound on running time of an algorithm. We must know the case that causes minimum number of operations to be executed. In the linear search problem, the best case occurs when x is present at the first location. The number of operations in the best case is constant (not dependent on n). So time complexity in the best case would be Θ(1) Most of the times, we do worst case analysis to analyze algorithms. In the worst analysis, we guarantee an upper bound on the running time of an algorithm which is good information. The average case analysis is not easy to do in most of the practical cases and it is rarely done. In the average case analysis, we must know (or predict) the mathematical distribution of all possible inputs. The Best Case analysis is bogus. Guaranteeing a lower bound on an algorithm doesn’t provide any information as in the worst case, an algorithm may take years to run. For some algorithms, all the cases are asymptotically same, i.e., there are no worst and best cases. For example, Merge Sort. Merge Sort does Θ(nLogn) operations in all cases. Most of the other sorting algorithms have worst and best cases. For example, in the typical implementation of Quick Sort (where pivot is chosen as a corner element), the worst occurs when the input array is already sorted and the best occur when the pivot elements always divide array in two halves. For insertion sort, the worst case occurs when the array is reverse sorted and the best case occurs when the array is sorted in the same order as output. ```

# ``` Asymptotic Notations```

``` ```
`The main idea of asymptotic analysis is to have a measure of efficiency of algorithms that doesn’t depend on machine specific constants, and doesn’t require algorithms to be implemented and time taken by programs to be compared. Asymptotic notations are mathematical tools to represent time complexity of algorithms for asymptotic analysis. The following 3 asymptotic notations are mostly used to represent time complexity of algorithms.`
`1) Θ Notation: The theta notation bounds a functions from above and below, so it defines exact asymptotic behavior.`
`A simple way to get Theta notation of an expression is to drop low order terms and ignore leading constants. For example, consider the following expression.`
`3n3 + 6n2 + 6000 = Θ(n3)`
`Dropping lower order terms is always fine because there will always be a n0 after which Θ(n3) has higher values than Θn2) irrespective of the constants involved.`
`For a given function g(n), we denote Θ(g(n)) is following set of functions.`
``````Θ(g(n)) = {f(n): there exist positive constants c1, c2 and n0 such
that 0 <= c1*g(n) <= f(n) <= c2*g(n) for all n >= n0}``````
`The above definition means, if f(n) is theta of g(n), then the value f(n) is always between c1*g(n) and c2*g(n) for large values of n (n >= n0). The definition of theta also requires that f(n) must be non-negative for values of n greater than n0.`
`2) Big O Notation: The Big O notation defines an upper bound of an algorithm, it bounds a function only from above. For example, consider the case of Insertion Sort. It takes linear time in best case and quadratic time in worst case. We can safely say that the time complexity of Insertion sort is O(n^2). Note that O(n^2) also covers linear time.`
`If we use Θ notation to represent time complexity of Insertion sort, we have to use two statements for best and worst cases:`
`1. The worst case time complexity of Insertion Sort is Θ(n^2).`
`2. The best case time complexity of Insertion Sort is Θ(n).`
`The Big O notation is useful when we only have upper bound on time complexity of an algorithm. Many times we easily find an upper bound by simply looking at the algorithm.`
``````O(g(n)) = { f(n): there exist positive constants c and
n0 such that 0 <= f(n) <= cg(n) for
all n >= n0}``````
`3) Ω Notation: Just as Big O notation provides an asymptotic upper bound on a function, Ω notation provides an asymptotic lower bound.`
`Ω Notation< can be useful when we have lower bound on time complexity of an algorithm. The Omega notation is the least used notation among all three.`
`For a given function g(n), we denote by Ω(g(n)) the set of functions.`
``````Ω (g(n)) = {f(n): there exist positive constants c and
n0 such that 0 <= cg(n) <= f(n) for
all n >= n0}.``````
`Let us consider the same Insertion sort example here. The time complexity of Insertion Sort can be written as Ω(n), but it is not a very useful information about insertion sort, as we are generally interested in worst case and sometimes in average case.`
`The following 2 more asymptotic notations are used to represent time complexity of algorithms.`
`Little ο asymptotic notation`
`Big-Ο is used as a tight upper-bound on the growth of an algorithm’s effort (this effort is described by the function f(n)), even though, as written, it can also be a loose upper-bound. “Little-ο” (ο()) notation is used to describe an upper-bound that cannot be tight.`
`Definition : Let f(n) and g(n) be functions that map positive integers to positive real numbers. We say that f(n) is ο(g(n)) (or f(n) Ε ο(g(n))) if for any real constant c > 0, there exists an integer constant n0 ≥ 1 such that f(n) 0.`

`Its means little o() means loose upper-bound of f(n).`

`In mathematical relation,`
`f(n) = o(g(n)) means`
`lim  f(n)/g(n) = 0`
`n→∞`
`Little ω asymptotic notation`
`Definition : Let f(n) and g(n) be functions that map positive integers to positive real numbers. We say that f(n) is ω(g(n)) (or f(n) ∈ ω(g(n))) if for any real constant c > 0, there exists an integer constant n0 ≥ 1 such that f(n) > c * g(n) ≥ 0 for every integer n ≥ n0.`
`f(n) has a higher growth rate than g(n) so main difference between Big Omega (Ω) and little omega (ω) lies in their definitions.In the case of Big Omega f(n)=Ω(g(n)) and the bound is 0<=cg(n)0, but in case of little omega, it is true for all constant c>0.`

`we use ω notation to denote a lower bound that is not asymptotically tight.`
`and, f(n) ∈ ω(g(n)) if and only if g(n) ∈ ο((f(n)).`

`In mathematical relation,`
`if f(n) ∈ ω(g(n)) then,`
`lim  f(n)/g(n) = ∞n→∞`

# ``` Analysis of Loops```

`1) O(1): Time complexity of a function (or set of statements) is considered as O(1) if it doesn’t contain loop, recursion and call to any other non-constant time function.`
``   // set of non-recursive and non-loop statements``
`For example swap() function has O(1) time complexity.`
`A loop or recursion that runs a constant number of times is also considered as O(1). For example the following loop is O(1).`
``````   // Here c is a constant
for (int i = 1; i <= c; i++) {
// some O(1) expressions
}``````
`2) O(n): Time Complexity of a loop is considered as O(n) if the loop variables is incremented / decremented by a constant amount. For example following functions have O(n) time complexity.`
``````   // Here c is a positive integer constant
for (int i = 1; i <= n; i += c) {
// some O(1) expressions
}

for (int i = n; i > 0; i -= c) {
// some O(1) expressions
}``````
`3) O(nc): Time complexity of nested loops is equal to the number of times the innermost statement is executed. For example the following sample loops have O(n2) time complexity`
``````
for (int i = 1; i <=n; i += c) {
for (int j = 1; j <=n; j += c) {
// some O(1) expressions
}
}

for (int i = n; i > 0; i -= c) {
for (int j = i+1; j <=n; j += c) {
// some O(1) expressions
}``````
`For example Selection sort and Insertion Sort have O(n2) time complexity.`
`4) O(Logn) Time Complexity of a loop is considered as O(Logn) if the loop variables is divided / multiplied by a constant amount.`
``````   for (int i = 1; i <=n; i *= c) {
// some O(1) expressions
}
for (int i = n; i > 0; i /= c) {
// some O(1) expressions
}``````
`For example Binary Search(refer iterative implementation) has O(Logn) time complexity.`
`5) O(LogLogn) Time Complexity of a loop is considered as O(LogLogn) if the loop variables is reduced / increased exponentially by a constant amount.`
``````   // Here c is a constant greater than 1
for (int i = 2; i <=n; i = pow(i, c)) {
// some O(1) expressions
}
//Here fun is sqrt or cuberoot or any other constant root
for (int i = n; i > 0; i = fun(i)) {
// some O(1) expressions
}``````
`See this for more explanation.`
`How to combine time complexities of consecutive loops?`
`When there are consecutive loops, we calculate time complexity as sum of time complexities of individual loops.`
``````   for (int i = 1; i <=m; i += c) {
// some O(1) expressions
}
for (int i = 1; i <=n; i += c) {
// some O(1) expressions
}
Time complexity of above code is O(m) + O(n) which is O(m+n)
If m == n, the time complexity becomes O(2n) which is O(n).
``````
`How to calculate time complexity when there are many if, else statements inside loops?`
`As discussed previously, worst case time complexity is the most useful among best, average and worst. Therefore we need to consider worst case. We evaluate the situation when values in if-else conditions cause maximum number of statements to be executed.`
`For example consider the linear search function where we consider the case when element is present at the end or not present at all.`
`When the code is too complex to consider all if-else cases, we can get an upper bound by ignoring if else and other complex control statements.`

# ``` Solving Recurrences```

`Many algorithms are recursive in nature. When we analyze them, we get a recurrence relation for time complexity. We get running time on an input of size n as a function of n and the running time on inputs of smaller sizes. For example in Merge Sort, to sort a given array, we divide it in two halves and recursively repeat the process for the two halves. Finally we merge the results. Time complexity of Merge Sort can be written as T(n) = 2T(n/2) + cn. There are many other algorithms like Binary Search, Tower of Hanoi, etc.`
`There are mainly three ways for solving recurrences.`
`1) Substitution Method: We make a guess for the solution and then we use mathematical induction to prove the the guess is correct or incorrect.`
``````For example consider the recurrence T(n) = 2T(n/2) + n

We guess the solution as T(n) = O(nLogn). Now we use induction
to prove our guess.

We need to prove that T(n) <= cnLogn. We can assume that it is true
for values smaller than n.

T(n) = 2T(n/2) + n
<= cn/2Log(n/2) + n
=  cnLogn - cnLog2 + n
=  cnLogn - cn + n
<= cnLogn``````
`2) Recurrence Tree Method: In this method, we draw a recurrence tree and calculate the time taken by every level of tree. Finally, we sum the work done at all levels. To draw the recurrence tree, we start from the given recurrence and keep drawing till we find a pattern among levels. The pattern is typically a arithmetic or geometric series.`
``````For example consider the recurrence relation
T(n) = T(n/4) + T(n/2) + cn2

cn2
/      \
T(n/4)     T(n/2)

If we further break down the expression T(n/4) and T(n/2),
we get following recursion tree.

cn2
/           \
c(n2)/16      c(n2)/4
/      \          /     \
T(n/16)     T(n/8)  T(n/8)    T(n/4)
Breaking down further gives us following
cn2
/            \
c(n2)/16          c(n2)/4
/      \            /      \
c(n2)/256   c(n2)/64  c(n2)/64    c(n2)/16
/    \      /    \    /    \       /    \

To know the value of T(n), we need to calculate sum of tree
nodes level by level. If we sum the above tree level by level,
we get the following series
T(n)  = c(n^2 + 5(n^2)/16 + 25(n^2)/256) + ....
The above series is geometrical progression with ratio 5/16.

To get an upper bound, we can sum the infinite series.
We get the sum as (n2)/(1 - 5/16) which is O(n2)``````
`3) Master Method:`
`Master Method is a direct way to get the solution. The master method works only for following type of recurrences or for recurrences that can be transformed to following type.`
``T(n) = aT(n/b) + f(n) where a >= 1 and b > 1``
`There are following three cases:`
`1. If f(n) = Θ(nc) where c < Logba then T(n) = Θ(nLogba)`
`2. If f(n) = Θ(nc) where c = Logba then T(n) = Θ(ncLog n)`
`3.If f(n) = Θ(nc) where c > Logba then T(n) = Θ(f(n))`

# ``` Amortized Analysis ```

`Amortized Analysis is used for algorithms where an occasional operation is very slow, but most of the other operations are faster. In Amortized Analysis, we analyze a sequence of operations and guarantee a worst case average time which is lower than the worst case time of a particular expensive operation.`
`The example data structures whose operations are analyzed using Amortized Analysis are Hash Tables, Disjoint Sets and Splay Trees.`
`Let us consider an example of a simple hash table insertions. How do we decide table size? There is a trade-off between space and time, if we make hash-table size big, search time becomes fast, but space required becomes high.`
`The solution to this trade-off problem is to use Dynamic Table (or Arrays). The idea is to increase size of table whenever it becomes full. Following are the steps to follow when table becomes full.`
`1) Allocate memory for a larger table of size, typically twice the old table.`
`2) Copy the contents of old table to new table.`
`3) Free the old table.`
`If the table has space available, we simply insert new item in available space.`
`What is the time complexity of n insertions using the above scheme?`
`If we use simple analysis, the worst case cost of an insertion is O(n). Therefore, worst case cost of n inserts is n * O(n) which is O(n2). This analysis gives an upper bound, but not a tight upper bound for n insertions as all insertions don’t take Θ(n) time.`
`So using Amortized Analysis, we could prove that the Dynamic Table scheme has O(1) insertion time which is a great result used in hashing. Also, the concept of dynamic table is used in vectors in C++, ArrayList in Java.`
`Following are few important notes.`
`1) Amortized cost of a sequence of operations can be seen as expenses of a salaried person. The average monthly expense of the person is less than or equal to the salary, but the person can spend more money in a particular month by buying a car or something. In other months, he or she saves money for the expensive month.`
`2) The above Amortized Analysis done for Dynamic Array example is called Aggregate Method. There are two more powerful ways to do Amortized analysis called Accounting Method and Potential Method. We will be discussing the other two methods in separate posts.`
`3) The amortized analysis doesn’t involve probability. There is also another different notion of average case running time where algorithms use randomization to make them faster and expected running time is faster than the worst case running time. These algorithms are analyzed using Randomized Analysis. Examples of these algorithms are Randomized Quick Sort, Quick Select and Hashing. We will soon be covering Randomized analysis in a different post.`
`Source: Internet`

``` ```